Force and Motion Practice Test 3
Force and Motion Practice Test #3 Number of MCQS: 50 Difficulty Level Moderate 70 Percent and Difficult 30 Percent
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Category: Force & Motion Topical (FAM)
Haya dropped a Brick freely from the top of Minar-e-Pakistan and it reaches the ground in 4 sec taking (g = 10ms2). Calculate the height of the Tower
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A particle is moving on a straight line path with constant acceleration directed along the direction of instantaneous velocity. Which of the following statements about the motion of particle is true
It is a straight line path hence the displacement = distance. Particle may not reverse the direction of motion due to constant acceleration. Average velocity is equal to average speed due to linear motion. Because object is accelerating, i.e. changing velocity with time, the average velocity is not equal to instantaneous velocity.
3 / 50
The statement of Newton's second law states
The rate of change of momentum of a body is directly proportional to the applied force and takes place in the direction in which the force acts.
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Two particles start from rest simultaneously and are equally accelerated. Throughout the motion, the relative velocity of one w.r.t. other is
If two particles start from rest simultaneously and are equally accelerated, they will have the same acceleration and will move together with the same velocity at all times.
Therefore, the relative velocity of one with respect to the other will be:
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A Truck weighing 50kg is moving with a velocity 10km/h on smooth horizontal rails. A mass of 20kg is add into it. find its final velocity.
Initial linear momentum of the system: Pi =mv=50 x 10 =500 kg m/sec Final Momentum of The System: Pf = (M + m)V
P= (50+20)V P= 70V According to Law of Conservation of Momentum: Final Momentum = Initial Momentum 70V = 500 V= 500/70 = 7.1 km/h
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Equation of motion can be used for
PICTURE FOR MOTION AND FORCE, different Motion Explained
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A particle is moving with a constant speed along straight line path. A force is not required to
8 / 50
If the slope of a graph is zero and so the displacement, then velocity is
If the slope of a displacement-time graph is zero, it means the displacement is constant over time.
Since velocity is the rate of change of displacement with respect to time, a constant displacement indicates that there is no change in displacement. Therefore, the velocity is zero.
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Ali cover a distance of 5 meter using a car and the Distance covered by him is directly proportional to the given time interval, (it will travelled with)
When distance is proportional to time, the ratio of distance and time remains constant. This means that in equal time intervals, the particle is travelling equal distances. So clearly the speed of the particle remains constant.
10 / 50
The acceleration of a moving object can be found from
The acceleration of a moving object can be found from Slope of Velocity time graph
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15 m/s can be written in km/h as ______
The formula for conversion is,
km/h = (18/5) x m/s.
Therefore,
15 m/s = 15 x (18/5)
= 54 km/h.
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When Slope is Negative Acceleration will be
On a velocity–time (v–t) graph, slope = Δv/Δt = acceleration .
A negative slope means that over a positive time interval (Δt > 0), the change in velocity (Δv) is negative (the line is falling).
So the acceleration is negative.
Physically, negative acceleration means the acceleration vector points opposite to the chosen positive direction—e.g., if you’re moving “forward,” a negative acceleration slows you down.
(Sometimes called “deceleration,” though strictly deceleration only refers to a decrease in speed, whereas negative acceleration could also speed you up in the reverse direction.)
13 / 50
A body moves with initial velocity 10ms−1. If it covers a distance of 20m in 2s, then the motion is
Suppose the acceleration is a then using the second equation of motion, s = ut + 1/2 at^2
and putting t = 2sec and u=10m/s
we get 20 = 10 × 2 + a × 2
or a = 0 that is uniform motion
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acceleration = negative , velocity of a car
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Gradient of line of velocity-time graph is tells us the
graph between velocity and time is a straight line which indicates that the slope is zero. Normally slope of velocity−time graph is acceleration but when it approaches a particular point then it becomes instantaneous acceleration.
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Haya thrown a Cricket Ball vertically upward with a speed of 50 m/s. The magnitude of its displacement after 6 s will be _______.
(g = 10 m/s2)
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Sawera place a block of 9.8 N on Table. and it is observed that The table surface exerts an upward force of 40 N on the block. Assume g = 9.8 m/s 2.
According to Newton's third law, if the table exerts 40N force on the block, the block will also apply same force on the table. As 9.8N<40N, the net force is in upward direction and thus, the block has an upward acceleration
NOTE: On This concept Similar MCQs were in NMDCAT 2021 but this is not Exact statement but the concept is same.
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If the displacement-time graph of an object is parallel to the time-axis, then it represents that the object is
Given that the time-displacement graph of a particle is parallel to the time-axis. That means if the distance-time graph of the object is parallel to the time axis then the particle has not covered any displacement with change in time. i.e. the particle is at rest.
So the change of displacement of the particle with respect to time is zero so the velocity of the particle will be zero.
19 / 50
In Half Revolution the total Distance cover by a body is equal to :
In completing 1 revolution, distance covered =2πR and displacement = 0,
for half Revolution: distance covered =πR and displacement = 2R
20 / 50
If a displacement-time graph of an object is a straight line parallel to the time axis, the object is
Displacement-time graph being parallel to the time axis, its slope is zero. Slope of a displacement-time graph measures velocity. So, velocity of the object is zero. The object is stationary.
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Which of the following is a possible unit for rate of change of momentum?
Rate of change of Momentum = Force
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Which of the following changes when a particle is moving with uniform velocity?
Acceleration =0, Velocity = Speed = constant As the position of particle changes with time so position vector is changing.
23 / 50
In a moving BUS Maryam thrown a Ball up, the Ball falls behind him. The BUS is
24 / 50
When a cannon shell explodes in mid-air,
According to the law of conservation of momentum, the momentum of a system remains constant if no external force acts on it.
1) When the shot is fired from a cannon and explodes in mid-air, no external force acts on it, and therefore, the linear momentum is conserved.
2) When the cannon explodes, the chemical potential energy stored in the explosives gets converted to kinetic energy due to the velocity acquired.
Therefore, when a shot is fired from a cannon and explodes in mid-air, the momentum will remain constant but kinetic energy will increase.
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If the speed of a straight line moving object changes, its speed is called _______.
If the speed of a straight line moving object changes, its speed is called Changed.
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A Car is moving on circle Circumference of radius R and completes half of the revolution. Then, the ratio of its displacement to distance is:
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If the velocity of an object changes from 3m/s to 4m/s during 0.5s the acceleration of the object is
Concept is change in velocity = 4 - 3 = 1
And total time = 0.5
Acceleration = 1/0.5 = 2
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if the slope of the velocity-time graph gradually decreases ,then the body is said to be moving with :
The slope of the velocity time graph represents the acceleration (or deceleration) of the object. If the slope is changing, either increasing or decreasing, that means the acceleration is changing.
Curtailment is an imprecise term. But, in general yes. A decreasing slope means the object is decelerating at an increasing rate.
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If displacement of a particle is zero, distance covered by it
When displacement is zero, particle may be at rest, therefore, distance travelled = 0.
Again, when displacement is zero, final position coincides with the initial position, distance travelled is not zero.
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During projectile motion , the horizontal component of velocity ;
In case of projectile motion the vertical component of particle's velocity changes continuously because of the force acting in vertical direction which is its own weight (mg).
But in the horizontal direction as there is no force acting on the object ; its horizontal velocity remains constant
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a ball with original momentum +5.0kgm/s hits a wall and bounces straight back without losing any kinetic energy . the change in momentum of the ball is
Pb represents momentum of ball (before hitting) Pb = 5.0 kg⋅m/s Pa represents momentum of ball (after hitting) Pa = −5.0 kg⋅m/s
ΔP:change of momentum
ΔP = Pa−Pb ΔP= −4.0 − 4.0
ΔP= −10 kg.m/s
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Only force acting on a bouncing ball is
Early Physics Concept
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Ratio of force and acceleration measures :
From Newton'a second law, force F=ma
⟹ F / a = m
Thus ratio of force and acceleration is equal to mass of the body.
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Which of the following can be zero when the particle is in motion for some time?
When the particle is in motion for some time, the speed and distance covered cannot be zero because the particle is moving. However, the displacement can be zero because the particle can come back to its initial position. In this case, the final position of the particle coincides with its initial position such that displacement, which is a distance with direction, becomes zero.
35 / 50
The velocity time graph of motion of an object starting from rest with uniform acceleration is a straight line
Uniform acceleration implies constant change of velocity with time, thus a straight slanting velocity-time graph that passes through the origin (from rest) but parallel to neither the time axis nor the velocity axis.
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A particle moves with uniform velocity. Which of the following statements about the motion of the particle is true?
The acceleration is the rate of change of velocity. Any change in velocity – with magnitude or direction – will result in acceleration. Therefore, in the given case, there exists no acceleration or speed variation. Also, the speed will not be zero. The acceleration of the particle in motion will be zero during a uniform velocity.
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A Car moves along a circle of radius ′3R′. What is the distance covered and displacement of the body after 2 complete rounds?
Here: r = 3R
and :- n= 2
Distance = 2 ( 2 π (3R)
Distance = 12 π R
38 / 50
A particle is moving along a circle such that it completes one revolution in 40 seconds. In 2 minutes , the ratio ∣displacement∣ : distance is
Thus, the particle will be back at it's initial position after 2 minutes. Thus, ∣displacement∣=0 so the ratio will Also Zero
39 / 50
A bullet weighing 50 gm leaves the gun with a velocity of 30 ms–1. If the recoil speed imparted to the gun is 1ms–1, the mass of the gun
40 / 50
Slope of Horizontal Line is
Slope of Horizontal Line: Zero
Slope of Vertical Line: Undefine / Infinity
41 / 50
When ball having a projectile motion is rising up, it
When a projectile is rising up, due to gravity the ball's vertical component of velocity continuously start decreasing because ball is travelling against the gravity . Now, at the highest point of a projectile path , the velocity in the vertical direction becomes zero.
42 / 50
If the gradient of a graph is negative, then the acceleration is
The picture below shows a velocity - time graph for an object with a velocity that decreases at a constant rate.
The straight line sloping downwards in the graph above shows that the objects velocity is decreasing as time goes by. This is called negative acceleration.
The straight line shows that it is constant negative acceleration. The slope of the line shows 1. the acceleration is negative because the line slopes downwards 2. how fast the negative acceleration is. The greater the slope, the faster the acceleration is.
43 / 50
If the velocity-time graph of an object is a straight line sloping downwards, the body has
The picture below shows a velocity - time graph for an object with an acceleration that increases.
The curve in the above graph shows that the acceleration is not constant because the slope is getting steeper. It is changing acceleration that increases as time goes by.
44 / 50
The time rate of change of momentum gives ,
Initial momentum P¹ = m × u
Final momentum P² = m × v
According to question,
dP/dt (rate of change of momentum) = (P² - P¹)/t
= m ( v - u ) / t
= m a
= Force
So, rate change of momentum is equal to Force.
45 / 50
A ball falling vertically from rest for 3 seconds travels very nearly:
Vi = 0; a = 9.8 m/s2; t = 3s
From s = v1t + (1/2)at2
s = (1/2) * 9.8 * 32 = 44.1 m.
46 / 50
The slope of the velocity time graph for retarded motion is:
Retarded motion is deceleration which implies negative acceleration, thus the slope of the velocity time graph for retarded motion is negative.
47 / 50
For an object moving in uniform circular motion, the direction of the instantaneous acceleration vector is:
For an object moving in uniform circular motion, the direction of the instantaneous acceleration vector is directed radially inward, perpendicular to the tangential velocity.
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A ball is thrown vertically upward with a velocity of 19.6 m/s. The time taken by the ball to reach the maximum height
u(initial velocity) = 19.6 m/s
at highest point v(final velocity)=0
using v=u + at
0 = 19.6 - 9.8 * t
t=19.6/9.8= 2s (time to reach max height)
49 / 50
Which of the following statement is false for motion with uniform velocity
For motion with uniform velocity, magnitude of displacement = distance
50 / 50
A stone is thrown upwards with initial velocity of 20 m s-1, the height that stone will reach would be
use the conservation of energy, all the kinetic energy that it has at the bottom is equal to the potential energy it will have at the top. Quick and dirty assumption that g = 10 m/s²
mv²/2 = mgh
v²/2 = gh
h = v²/2g
h = (20 m/s)² / (2 × 10 m/s²)
h = (400 m²/s²) / (20 m/s²)
h = (400/20) (m² × s²) / (m × s²)
h = 20 m
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