as F = ma,
where F is the net force, m is the mass of the object, and a is the acceleration.
Plugging in the values you provided, you get:
a = F/m = 5.0 N / 7.0 kg = 0.71 m/s^2

So the acceleration of the bowling ball is 0.71 m/s^2.

To improve the jumping record in long jump, the athlete should aim to maximize the distance they can cover. In order to do this, they should aim to jump at an angle of 45 degrees, which will result in the maximum range for the projectile (the athlete's body in this case).

Jumping at an angle greater than 45

Jumping at an angle greater than 45 degrees will result in a higher initial vertical velocity and a lower initial horizontal velocity, which means that the athlete will spend more time in the air and less time moving horizontally. This will result in a shorter distance covered.

Jumping at an angle less than 45

Jumping at an angle less than 45 degrees will result in a lower initial vertical velocity and a higher initial horizontal velocity, which means that the athlete will spend less time in the air and more time moving horizontally. This will also result in a shorter distance covered.

Therefore, to improve their jumping record, the long jumper should aim to jump at an angle of 45 degrees, which will result in the maximum range and distance covered.

9.8 m/s^2. This is the acceleration due to gravity on Earth. The ball will accelerate downward at a rate of 9.8 m/s^2 until it reaches terminal velocity, which is the maximum speed that the ball can reach due to air resistance. The speed at which the ball reaches terminal velocity depends on the shape and size of the ball and the density of the air.

You can also use a velocity-time graph to determine the distance (or Displacement) traveled by an object. The area under the curve of a velocity-time graph represents the distance (Or displacement) traveled by the object.

sum of 43 and 47 is 90  so at these two we have same Range easy trick is that take sum if its 90 then choose it

9.8 m/s^2. This is the acceleration due to gravity on Earth. The ball will accelerate downward at a rate of 9.8 m/s^2 until it reaches terminal velocity, which is the maximum speed that the ball can reach due to air resistance. The speed at which the ball reaches terminal velocity depends on the shape and size of the ball and the density of the air.

Since the ball is moving first up and then down, the best way to look at it is as two halves.

The equation for motion is: Vf = Vi + a*t (where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and t is the time).

Since the ball is at 0 speed when at the top (end of the first half and just before starting to fall down) and gravity is "working" against the upwards movement, the equation becomes:

0 = 19.6 + (-9.8) * t

Therefore:

t = 2

The second half takes the same time down, since the ball is falling from the same height it reached at the end of the first half. So the total time is 4 seconds.

Since the ball's speed is changing, we should use the following equation to find the distance traveled (for each half):

x = Vo * t + 1/2 * a * t2

So:

x = 19.6 * 2 + 1/2 * (-9.8) * 22 = 39.2

The ball traveled 19.6 meters twice, for a total distance of 39.2 meters.

The average speed is the total distance traveled divided by the total time:

avg speed = 39.2/4 = 9.8 m/s

we Know: 
impulse = F.Δt
impulse = Ns

The time taken by the projectile to reach the ground can be calculated using the formula:

t = √(2h/g)
where h is the initial height of the projectile (490m in this case), g is the acceleration due to gravity (9.8 m/s²), and t is the time taken by the projectile to reach the ground.

Plugging in the values, we get:

t = √(2*490/9.8) = √(100) = 10 seconds

So the time taken by the projectile to reach the ground is 10 seconds.

The change in momentum of the ball is equal to the final momentum minus the initial momentum. We can use this relationship to calculate the change in momentum of the ball as follows:
Δp = p2 - p1
= (-4.0 kgm/s) - (4.0 kgm/s)
= -8.0 kg*m/s