When a body is dropped from a tower, its velocity increases continuously due to the gravitational force pulling it downward.

This acceleration causes the body to gain speed as it falls. At the same time, the body's potential energy decreases because it is converting into kinetic energy—the energy of motion—as the body descends.

Explanation:

When a particle is moving with uniform velocity then its speed also zero and acceleration become zero.

The position vector of the particle changes as time progresses, even if the particle is moving with uniform velocity, because its location in space is continuously changing.

During the flight of an oblique projectile:

• The horizontal velocity component (Vx) remains constant.
• The vertical velocity component (Vy) first decreases, reaches a minimum, and then increases.

Explanation:

Hint: An External Force by gravity is Present Throughout the Motion so Momentum cannot Be Conserved

Only the horizontal component of velocity and acceleration remain constant for a projectile, as they are not affected by the vertical forces of gravity.

Explanation of Incorrect Options:

Vertical component of velocity and kinetic energy: Both change continuously due to gravity.

Potential energy and kinetic energy: They constantly convert from one form to another throughout the projectile's motion.

Potential energy and acceleration: Acceleration is always due to gravity, which affects both potential and kinetic energy, making them change.

A force can cause a stationary object to start moving, a moving object to decrease speed, and a moving object to change its direction of motion.

To find the magnitude of the displacement of the car, we must represent each velocity of the car as a vector. We will then add the vectors. Finally, we will find the magnitude of the resulting velocity vector, which will give us speed.

The cannon ball has a two-dimensional motion, specifically projectile motion. Any two-dimensional motion consists of two one-dimensional motions happening at the same time. This is why we break vectors into components, so we can analyze each one-dimensional motion separately. The motion in the y-axis and the x-axis are connected by the time variable, since they happen at the same time. For projectile motion, we have that on the y-axis (the vertical axis) a constant acceleration (gravity) is acting on the cannon ball. For the y-axis motion with constant acceleration or free fall (which is motion with constant acceleration where the acceleration is gravity) are correct choices. On the x-axis (the horizontal axis), there is no acceleration acting on the cannon ball horizontally. Therefore, on the x-axis the cannon ball experiences motion with constant velocity. Then the only answer choice that describes the motion of the cannon ball in each axis correctly is: y-axis: motion with constant acceleration and x-axis: motion with constant velocity.

To find the average velocity, the displacement needs to be measured. The displacement the difference between The final position and the initial position.

75m−50m=25m

Using the equation for velocity, velocity=displacement/time, we can find the average velocity.

v=25/5=5ms

We are given the time that the ball is in the air and the acceleration. Since the ball is dropped, we can also tell that the initial velocity is zero (starts from rest). Using these given values, we can calculate the final velocity using the appropriate motion equation.

The final velocity is negative because the ball is traveling downward; however, the question asks for speed, allowing us to disregard the vector indicator. Speed cannot be negative.

We are given the time that the ball is in the air and the acceleration. Since the ball is dropped, we can also tell that the initial velocity is zero (starts from rest). Using these given values, we can calculate the final velocity using the appropriate motion equation.

The resulting displacement is negative because the ball is traveling downward; however, the height will be the absolute value of the displacement, giving out final answer.

Explanation:

Straight line with constant slope on s–t graph means constant speed.